for loop doesn't work


 
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# 1  
Old 12-30-2008
for loop doesn't work

I have a script which uses below for loop:

for (( i = 0 ; i <= 5; i++ ))
do
echo "Welcome $i times"
done


But when I run the script, it gives error message:
Syntex Error : Bad for loop variable

Can anyone guide to run it?

Thanks in advance.
# 2  
Old 12-30-2008
for ((a=1; a <= LIMIT ; a++)) # Double parentheses, and "LIMIT" with no "$".
do
echo -n "$a "
done

- nilesh

Last edited by ynilesh; 12-30-2008 at 01:35 AM..
# 3  
Old 12-30-2008
Nilesh, thanks for quick response.
What should be syntex to get the required output?

Please respond.

Deepak
# 4  
Old 12-30-2008
Code:
$ for (( i = 0 ; i <= 5; i++ )); do echo "Welcome $i times"; done

$ for i in $(seq 0 5); do echo "Welcome $i times"; done

$ for i in `seq 0 5`; do echo "Welcome $i times"; done

$ for i in 0 1 2 3 4 5; do  echo "Welcome $i times"; done

// Jadu
# 5  
Old 12-30-2008
hay deepak..... run your script with bash instead if running it as sh.

- nilesh
# 6  
Old 12-30-2008
Hi Nilesh/Jaduks,
Thanks for quick suggestions. You guys are making this forum more relevent. Keeping helping like this. Thanks a ton again.


Deepak
# 7  
Old 12-30-2008
What was the mistake in the first script I sent?
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