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shell "if" condition not executed

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# 1  
Old 12-15-2008
shell "if" condition not executed
Hi,

The below script should should create a file "COUNTFILE.log" if not found. But I am trying to run this and it is not creating the file .


#!/bin/sh
find . -name "COUNTFILE.log" > /dev/null 2>&1
if [ $? -eq 1 ]; then
echo 0> COUNTFILE.log
fi



Please advice why it is not creating the "COUNTFILE.log"

Regards
# 2  
Old 12-15-2008
Insert an
Code:
echo $?

right after the find. You will see that it is a zero because find encounters no error and exits successfull.

If you know the exact path where this file should be, maybe better test with something like
Code:
...
if [[ ! -e yourfile ]]; then
   touch yourfile
fi
...

Also it would be nice if you start to use [ code ] tags Smilie
# 3  
Old 12-15-2008
Kindly explain what are code tags...lot of experts are advising me to use code tags

Regards
# 4  
Old 12-15-2008
These are code-tags:

Code:
...

When writing your message, mark the code and press the little #-Button
in the toolbar. Its the fourth from the right.

HTH Chris
# 5  
Old 12-15-2008
ok ...you mean to say that my message should be presented like this.


Hi,

The below script should should create a file "COUNTFILE.log" if not found. But I am trying to run this and it is not creating the file .


Code:
#!/bin/sh
find . -name "COUNTFILE.log" > /dev/null 2>&1 
if [ $? -eq 1 ]; then 
     echo 0> COUNTFILE.log 
fi



Please advice why it is not creating the "COUNTFILE.log"

Regards
Last edited by zaxxon; 12-15-2008 at 09:03 AM.. Reason: Check now for code tags :)
# 6  
Old 12-15-2008
Great. Perhap it works this way:

Or remove the "x" in the tags: [xCODE] [x/CODE]
# 7  
Old 12-15-2008
I edited your post and added some so just edit it yourself again and you'll see them.
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