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Results of "find" to an array

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# 1  
Old 12-05-2008
Results of "find" to an array
I am looking to search a directory for a folder or file and when it finds any hits I want it to store those hits in an array so I can work with those hits later on.

I have been trying to do something like this but it isn't putting results into an array like I would like, is it syntax or is this not possible?

Code:
TARGET="MyRoot"
START_PATH="/Users/rtipton/Desktop/"

PATH_COUNT=0

find "$START_PATH" -type d \( -iname "$TARGET" \) -exec PATH_RESULTS[PATH_COUNT=$PATH_COUNT+1]=`echo {}` \;

Any ideas?
Rob
# 2  
Old 12-05-2008
Why don't you use a loop?

Code:
TARGET="MyRoot"
START_PATH="/Users/rtipton/Desktop/"

PATH_COUNT=0

find "$START_PATH" -type d \( -iname "$TARGET" \) \; | 
while read result
do
  PATH_RESULTS[$PATH_COUNT]="$result"
  echo "${PATH_RESULTS[$PATH_COUNT]}"
  # more code
  #
  let PATH_COUNT=PATH_COUNT+1
done

Regards
# 3  
Old 12-05-2008
Quote:
Originally Posted by Franklin52
Why don't you use a loop?

Code:
TARGET="MyRoot"
START_PATH="/Users/rtipton/Desktop/"

PATH_COUNT=0

find "$START_PATH" -type d \( -iname "$TARGET" \) \; | 
while read result
do
  PATH_RESULTS[$PATH_COUNT]="$result"
  echo "${PATH_RESULTS[$PATH_COUNT]}"
  # more code
  #
  let PATH_COUNT=PATH_COUNT+1
done

Regards
Ok I tried this out but once the find + loop is finished the array is lost and the values are gone, I need to be able to work with the data in the array later on and outside of the loop. Any way to do that? put the data into a global array?

Thanks for the help,
Rob
# 4  
Old 12-05-2008
If you want to use the array outside of the loop you must avoid to pipe the result. The pipe mechanism starts a subshell and parent shells don't inherit variables of a child shell.

Code:
TARGET="MyRoot"
START_PATH="/Users/rtipton/Desktop/"

PATH_COUNT=0

for result in "`find "$START_PATH" -type d \( -iname "$TARGET" \) \;`"
do
  PATH_RESULTS[$PATH_COUNT]="$result"
  echo "${PATH_RESULTS[$PATH_COUNT]}"
  # more code
  #
  let PATH_COUNT=PATH_COUNT+1
done

Regards
# 5  
Old 12-05-2008
Quote:
Originally Posted by Franklin52
If you want to use the array outside of the loop you must avoid to pipe the result. The pipe mechanism starts a subshell and parent shells don't inherit variables of a child shell.

Code:
TARGET="MyRoot"
START_PATH="/Users/rtipton/Desktop/"

PATH_COUNT=0

for result in "`find "$START_PATH" -type d \( -iname "$TARGET" \) \;`"
do
  PATH_RESULTS[$PATH_COUNT]="$result"
  echo "${PATH_RESULTS[$PATH_COUNT]}"
  # more code
  #
  let PATH_COUNT=PATH_COUNT+1
done

Regards
Hey thanks again, this worked to make the data global but now with this option, find provides all the paths into 1 variable instead of each path being it's own value in the array.

PATH_RESULTS ends up holding the value of all of the results rather than PATH_RESULTS[x] being 1 result each, any way to combine the pipe option which worked this way with the global variable result of this version?

Rob
# 6  
Old 12-05-2008
It looks like I'll be able to adapt to work within the piped loop without need for the data later in the script, thanks for your help!!

-Rob
# 7  
Old 12-05-2008
Try to remove the \; at the end of the find command.

Code:
for result in "`find "$START_PATH" -type d \( -iname "$TARGET" \)`"

Regards
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