Extracting fields from file


 
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# 1  
Old 12-05-2008
Extracting fields from file

I am need to extract a number of values from a file, put have now clue how to do this.

The file looks like this:
# My file
Dest=87;CompatibleSystemSoftwareVersion=2.5300-;
Dest=87;ImageVersion=000061f3;SystemSoftwareVersion=2.5300;CDN=http://my.backup.com/download.txt;CDN_Timeout=30;

I would like to extract the value for SystemSoftwareVersion and CDN into two variables as part of a bash-script so that I can use them further.

Appreciate the help...
# 2  
Old 12-05-2008
One way as a start:
Code:
ARR1=`sed 's/.*SystemSoftwareVersion=\([^;]*\);.*/\1/' yourfile`
ARR2=`sed -n '{s/.*;CDN=\([^;]*\);.*/\1/p}' yourfile`

echo $VAR1
2.5300- 2.5300

echo $VAR2
http://my.backup.com/download.txt

Not sure if that is what you need. Maybe it's better to load them in an array so you can work them if they form up a pair, ie. are associated each other or something like that.
# 3  
Old 12-05-2008
Quote:
Originally Posted by zaxxon
One way as a start:
Code:
ARR1=`sed 's/.*SystemSoftwareVersion=\([^;]*\);.*/\1/' yourfile`
ARR2=`sed -n '{s/.*;CDN=\([^;]*\);.*/\1/p}' yourfile`

echo $VAR1
2.5300- 2.5300

echo $VAR2
http://my.backup.com/download.txt

Not sure if that is what you need. Maybe it's better to load them in an array so you can work them if they form up a pair, ie. are associated each other or something like that.
Thanks this is brilliant - I had to make some minor adjustments, but now is exactly what I need:
CURR_FIRMWARE=`sed -n 's/.*;SystemSoftwareVersion=\([^;]*\);.*/\1/p' ${PS3_VERSION_FILE}`
CURR_URL=`sed -n 's/.*;CDN=\([^;]*\);.*/\1/p' ${PS3_VERSION_FILE}`
# 4  
Old 12-06-2008
below script should be able to find any number inside your file, you may need to modify it to address your requirement.

Code:
open FH,"<a.txt";
while(<FH>){
	tr/\n//d;
	my @tmp=split(";",$_);
	foreach(@tmp){
		print "Var[$1]: $2\n" if (m/(.*)=([0-9][0-9]*\.*[0-9][0-9]*)/);
	}
}
close FH;

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