Shell Programming and Scripting

Hi all,


I have an awk basic question.


file.text


Our Location:
Our home has light yellow siding,
and is a duplex on Main Street,
across from the High School,
and across the lane from the Health Center


If I run:


cat file.txt | awk '{print $2}' | grep „Location“


then the script is working fine.


But if the first line on the file.text is changed to „My and your Location“ then the script does't work. Is there any posibility to give the awk a regular expression, for expample: cat file1 | awk '{print $Location}' ?
Is there any posibility that I don't have to defin the exact column number?

cat and grep is redundant if you use awk or sed, this should print the lines that match the pattern:

Code:

awk '/Location/' file.txt

With sed:

Code:

sed -n  '/Location/p' file.txt

grep was made for that

Code:

grep Location file

Sure! I have any trouble with profession blindness.

yes, but the standard output is a line and not a single word.

maybe I ask the question wrong,
I mean how can I grep one value (egular expression exp. Loca* ) in an line if the position (first or second column) is not defined?
And the result is only the word.

With this process I will test if the value is available "match" or not?
But maybe is sed the better tool for this.

Yes, you do

Now you want first column or second column or not defined?

Code:

awk '/Location/{print "BINGO"}' file
or ..
sed -n '/Location/s/.*/BINGO/p' file
or..
grep -q Location file  && echo BINGO