Shell Programming and Scripting

Hello All,

I am new to Shell script world. Please help me out with following query..

OS: AIX
Shell Script I am trying to execute:
showStatus ()
{
echo $1
//Actually I need to do something with the input here...
}

./serverStatus.sh | grep STARTED | awk '{print $5}' | showStatus

Result: nothing comes out on the console

Output of ./serverStatus.sh when run alone:
ADMU0503I: Retrieving server status for all servers
ADMU0505I: Servers found in configuration:
ADMU0506I: Server name: server1
ADMU0506I: Server name: nodeagent
ADMU0508I: Server name: "PVSDEV_AS1"
ADMU0508I: The Application Server "PVSDEV_AS1" is STARTED
ADMU0509I: The Application Server "server1" cannot be reached. It appears to be stopped.
ADMU0508I: The Node Agent "nodeagent" is STARTED

Expected Result:
PVSDEV_AS1
nodeagent
above 2 lines should be printed on the console (Again I need to do something with this in the function above.. but as of now trying to print it)

My Question:
Is my approach in the shell script right? or should I follow a different way?

Thank you in advance.

Cheers,
Raj

Just wondering if my question is clear to all. To be short and sweet, I want the output of a sh file to function in my script.

Cheers,
Raj

Here's one approach:

Code:

./serverStatus.sh | grep STARTED | awk '{print $5}'  | while read VALUE ; do
   showStatus $VALUE
done

Thanks a lot jimbalaya.. it worked like charm...

Cheers,
Raj