how to log top command


 
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Old 02-08-2006
LOAD value

Quote:
Originally Posted by Kelam_Magnus
Perderabo,

I am running 11.0 with term of vt320. I think top is the standard version for my host.
HP-UX myhost B.11.00 A 9000/800 624339393 two-user license

I used this command.

top -h -d 1 -f file.top

My output was this.

# cat file.top
Load averages: 0.21, 0.22, 0.24
657 processes: 638 sleeping, 18 running, 1 zombie
Cpu states: (avg)
LOAD USER NICE SYS IDLE BLOCK SWAIT INTR SSYS
0.21 14.2% 0.0% 0.8% 85.0% 0.0% 0.0% 0.0% 0.0%
Memory: 2327724K (972304K) real, 2098712K (937484K) virtual, 24059800K free Pa2

CPU TTY PID USERNAME PRI NI SIZE RES STATE TIME %WCPU %CPU COMMAND
4 ? 22458 oracle 231 20 1511M 197M run 55:13 100.15 99.98 oracletcoe
1 ? 27456 oracle 152 20 203M 162M run 228:56 2.97 2.97 native_th
7 ? 782 root 154 20 1544K 128K sleep 546:04 1.49 1.49 syncer
6 ? 39 root 152 20 1856K 0K run 74:17 1.27 1.27 vxfsd
7 ? 22736 oracle 154 20 1316M 2864K sleep 0:39 0.91 0.91 oracletcone
3 ? 399 applmgr 154 20 401M 5328K sleep 2:10 0.73 0.73 oraclecfas1
0 ? 1805 applmgr 156 20 428M 3736K sleep 1:12 0.58 0.57 ora_snp0_C1
7 ? 3 root 128 20 32K 0K sleep 130:05 0.43 0.43 statdaemon
0 ? 1327 oracle 156 20 1331M 13104K sleep 2:18 0.42 0.42 oracletcone
3 ? 11620 applmgr 154 20 397M 2096K sleep 15:28 0.34 0.34 oraclecfas1
3 ? 6607 patrol 154 30 25836K 21828K sleep 869:15 0.34 0.34 PatrolAgent
3 ? 14314 applmgr 156 20 423M 27788K sleep 44:15 0.30 0.30 ora_qmn0_c1
1 ? 11810 applmgr 154 20 397M 1984K sleep 47:54 0.26 0.26 oraclecfas1
0 ? 27120 applmgr 154 20 399M 3248K sleep 0:01 0.24 0.24 oracleCFAS1
1 ? 22706 applmgr 154 20 398M 2144K sleep 2:37 0.23 0.23 oracleCFAS1
5 ? 6889 root 152 20 35912K 13016K run 15:12 0.22 0.22 mxagent
Just wondering the value under LOAD... Is this a percentage? There's no % sign??
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