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replace a word in a file only first 10 occurances

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# 1  
Old 11-12-2008
Bug replace a word in a file only first 10 occurances
file.txt contains
abc :-X 1234 :-X fjhfkf :-X ffwerw :-X fdfgetw :-X hwfhe89 :-X

in the this file there are 6 occurance of -X
i want to replace only first 3 occurances of '-X' with 'XY'
and write back to same file.
# 2  
Old 11-12-2008
Try:

Code:
sed -e 's/X/XY/1' -e 's/X/XY/2' -e 's/X/XY/3' < filename

# 3  
Old 11-12-2008
Thats really quick reply, appreciate the response. I had already tried that, but i want to put it in a loop.
for example there can be 1000 occurances out of which i want to replace only first 500 occurances.

following line inside loop will affect take too much time if the txt file is 100MB
sed -e 's/X/XY/$i'

Please suggest sed or awk program.
# 4  
Old 11-12-2008
Try:
Code:
v=10
awk -vvar=$v 'BEGIN{cnt=1;} { while((match($0,"-X")>0)&& (cnt <=var)){ sub(/-X/,"XY",$0); cnt++;} print; }' < filename

# 5  
Old 11-12-2008
this is awsome, works great....... Thanks buddy.
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