Shell Programming and Scripting

Hi All,

I have a data as follow:

0
0
0
X
X
0
X
X
X
0
X
0
0
X
0
0
....
....


I want to count how many times the consecutive occurrence of Xs. As

000 XX0 XXX0 X0 0 X0 0000 X0 XX0 000 XXXX0 X0 XX0 X0
-----1----2----3----1-------1---2---------1----2--3---4 (I want to print　out this)

Please, let me know how to write an awk code for this..

Thanks

I don't see the logical to get the desired output with the given data.
Why don't you show us the code you have so far, and tell us how it misbehaves?

Hi Franklin52,


Thanks for the quick respond..


Ok, I try to explain more details....



If every X followed by 0 is count as occurrence 1
e.g: X0 , XX0, XXX0, XXXX0, so on... count as occurrence 1


For example, if there is a range of data like this:
000X0X0000X0XX0XXX0XX00000X000


then, we can distinguishes like this:

000 X0X0 000 X0XX0XXX0XX0 0000 XXXXX0 00

X0X0 = count as occurrence 2 (there are two X0s)

X0XX0XXX0XX0 = count as occurrence 4
There are X0, XX0, XXX0, XX0


XXXXX0 = count as occurrence 1



So, the desired output of example above is:
2
4
1



(Remember, The range of data is displayed in row by row)


I hope you can understand my explanation


Thanks

Code:

echo "000 X0X0 000 X0XX0XXX0XX0 0000 XXXXX0 00" |perl -ne 'foreach(split){
@a=m/X0/g;
print $#a+1,"-";
}'

Code:

0-2-0-4-0-1-0-

Hi Summer Cherry,

Thanks for the Perl Code..

Do you have any idea how to write it in Awk?
FYI, my Input Data range is displayed line by line.

Thanks

Try this awk:

Code:

echo "000 X0X0 000 X0XX0XXX0XX0 0000 XXXXX0 00"|awk '{print NF-1}' RS=" " FS="X0" ORS="-"

Another one, with line number before the numbers of occurrences:

Code:

awk '{
  print "Line : " NR
  for(i=1;i<=NF;i++){
    n=gsub("X0","",$i)
    if(n){print n}
  }
}' file