Shell Programming and Scripting

sed 's/^/hello gaurav "/g;s/$/"/g' abc.txt > xyz.txt

Try this:

Code:

sed 's/.*/Some text "&/' file > newfile

sed 's/^/hello gaurav "/g;s/$/"/g' abc.txt > xyz.txt

The reason is that there is no "\n" at the end of the line as far as sed is concerned. There is a far more easy device to match line ends or line beginnings, which you have already seen used here:

"^" at the beginning of a regex means "line beginning". "x" finds any x, "^x" finds only an "x" on first position of the line.

"$" at the end of a regex means "line end". "x$" would match only a line ending with "x".

There is another metacharacter you have seen used here: "&" in a replacement string this means "everything that has been matched by the regex". Example:

echo "xxxabcxxx" | sed 's/abc/y&y/' ==> will give "xxxyabcyxxx"
echo "xxxabcxxx" | sed 's/ab/y&y/' ==> will give "xxxyabycxxx"

You should now be able to create a correct sed script yourself. In fact you have two ways of doing it shown here.

I hope this helps.

bakunin

thanks everybody for their help

i am tried the following script and it works fine

sed "s/^/prefix/;s/$/suffix/" oldfile > newfile