Shell Programming and Scripting

Please assist with awk scirpts:

I need to remove items from a file in a batch:

The file that I will remove from has the following format:

abc00tef:10.81.12.3
abc01tef:10.81.12.3
abc02tef:10.81.12.3
abc03tef:10.81.12.3
abc04tef:10.81.12.3
abc05tef:10.81.12.3


I have a file which is in following format, and will remove line from above file.
the script will look for field before colon( and will remove entire line.

abc00tef
abc01tef
abc02tef

so from the original file will have:

abc03tef:10.81.12.3
abc04tef:10.81.12.3
abc05tef:10.81.12.3


Thanks

file1 is the original - file2 has the list of items to remove

Code:

grep -v -f file2  file1 > newfile

Jim M's solution is probably the simplest and most straight-forward.

To do in awk, one approach would be to
load the values into an array
then read full file; based on if your phrase is in the array,
then write or don't write the data out

I tried the this approach but I am getting the following error:

grep: illegal option -- f
Usage: grep -hblcnsviw pattern file . . .

Try the same, but use egrep instead of grep.

Thanks, egrep worked, thank you very much.