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calculating endless columns

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Top Forums Shell Programming and Scripting calculating endless columns
# 15  
Old 11-10-2008
Thank you soo much. I do intend to buy a book on it..

since the total of odd and even column have become $1 and $2 respectively, i tried to do few substitions to divide the $3/$1 and $4/$2 ...$5/$1, $6/$2...but i seem to run into shift problems.


$
$ cat calc
#! /usr/bin/ksh
bc |&
print -p scale=2
exec < sample
while read line ; do
set -- $line
output=""
while (($#)) ; do
if (($3 / $1)) ; then
print -p "$3/$1)"
read -p result1
print -p "$4 / $2)"
read -p result2
output="${output}$(echo $result1 $result2//c"
shift 2
else
output="${output}$(echo 00.00 00.00 \\c)"
 fi
done
echo
done
exit 0
$ ./calc

PS: help one last time. .pleasee...:-)
# 16  
Old 11-10-2008
In the code you set odd and even as 0.00..
does it mean that the variables are preset to 2 decimal places???
what is it doing ???
# 17  
Old 11-10-2008
I really have no idea what you're talking about. The script does what you asked... just cut and paste it.

The input data is considered two columns at a time and they are $1 and $2. The "shift 2" makes the current $1 and $2 vanish. Then what used to be $3 and $4 become the new $1 and $2. The odd and even column is $odd and $even. They must get reset to zero for each line of input. And normally echo would output lines including a newline character at the end. You don't want two numbers per line so we need to surpress that newline character and \\c does that. We need to store the calculated %'s in output, because we won't have a finished even and odd until we finish with the line.
# 18  
Old 11-10-2008
okk.. understood the description... i did copy and paste the code... but i i had to divide the even columns by the sum of even columns and odd by sum of odd columns.. $3/$1, $4/$2,$5/$1,$6/$2......would the code in red be right??

if (($3 + $4)) ; then
print -p "$3 * 100 / ($1)"
read -p result3
print -p "$4 * 100 / ($2)"
read -p result4#
echo $result3 $result4 \\c
shift 2
else
echo 00.00 00.00 \\c
Last edited by chronicx; 11-10-2008 at 04:11 PM..
# 19  
Old 11-10-2008
Well I finally understand that "endless" in the title.

I don't see anything in red. But you're not very close. It's wrong to keep trying to use $3 and $4. The totals are calculated during the loop. Until the loop finishes, there no totals available. You will need a second loop to reprocess the data after the totals have been found.

Had you given the real requirements on the weekend I could have written the script you needed instead of one you can't use. Smilie I don't have time now. Maybe someone else can write the next couple of versions for you.
# 20  
Old 11-12-2008
awk '{
for(i=1;i<=NF;i++)
{ if(i%2)
printf("%.2f ",$i*100/($i+$(i+1)))
else
printf("%.2f ",$i*100/($i+$(i-1)))
}
print ""
}' filename
# 21  
Old 11-12-2008
Thank you..i really appreciate your help.. however it is givin out wrong output..
Code:
47.46 52.54 45.83 54.17 51.62 48.38 41.37 58.63 32.00 68.00 56.42 43.58 57.52 42.48 
43.33 56.67 56.56 43.44 49.05 50.95 42.85 57.15 100.00 0.00 0.00 100.00 11.49 88.51 
45.54 54.46 41.66 58.34 52.18 47.82 26.82 73.18 61.54 38.46 57.70 42.30 33.33 66.67 
42.84 57.16 20.00 80.00 34.37 65.63 0.00 100.00 59.26 40.74 100.00 0.00 43.43 56.57 
40.51 59.49 50.00 50.00 25.53 74.47 35.55 64.45 84.42 15.58 47.53 52.47 0.00 100.00

actual input
Code:
284.73 315.22 45.83 54.16 51.61 48.38 41.37 58.62 32.00 68.00 56.41 43.58 57.51 42.48
259.94 340.02 56.55 43.44 49.05 50.94 42.85 57.14 100.00 0 0 100.00 11.49 88.50
273.20 326.74 41.66 58.33 52.17 47.82 26.82 73.17 61.53 38.46 57.69 42.30 33.33 66.66
257.05 342.92 20.00 80.00 34.37 65.62 0 100.00 59.25 40.74 100.00 0 43.43 56.56
243.02 356.94 50.00 50.00 25.53 74.46 35.55 64.44 84.41 15.58 47.53 52.46 0 100.00


sample output of the values to turn out -
16.09 17.18 18.12 15.34 .....

dividng $3/$1 , $4/$2, $5/$1, $6/$2......................
Last edited by chronicx; 11-12-2008 at 04:00 AM..
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