Shell Programming and Scripting

Hi,

Data file named parameter contains :

DB=y
Alter_def.sql
Create_abc.sql

SQL=y
database.sql
my_data.sql

To read this file I use

var_sql=$(awk -F= '$1 == "SQL" { print $2 }' parameter.txt)
if [ $var_sql = "y" -o $var_sql = "Y" ]
then
sql_f_name=`grep "\.sql" parameter.txt`
echo $sql_f_name
fi

So this code returns all the file name. But I want only
database.sql
my_data.sql

these two file. Can any one suggesst me how can I get the desired result
without changing the search string(`grep "\.sql" parameter.txt`).

All you need is:
(use nawk or /usr/xpg4/bin/awk on Solaris)

Code:

awk '/SQL=[Yy]/&&sub(/ *[^ \n]*\n/,"")' RS= parameter.txt

Thanks radoulov....it's working fine