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Need to print only selected char in a string..?

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# 1  
Old 10-21-2008
Need to print only selected char in a string..?
Hi,

I want to print particular chars in a string. for example
ie.,

consider " dear,. roopa$#09%~`';'][\.@ " as the example string. Here, I want to print only alphanumeric chars..

suppose , if i want only alphanumeric... value would be "dear roopa09"
suppose , if i want some spl char(,) with alphanumeric...ans would be "dear, roopa09"
It could be anything, like only numeric chars or alphabetic or only . symbol or * symbol... anything.

plz, give ur valuable solution.

Thanx,
Balan Smilie
# 2  
Old 10-21-2008
You need to read about POSIX character types in the tr man page [:alpha:], [:space:], etc.

Code:
 echo 'dear,. roopa$#09%~`][.@* ' | tr -d '[:punct:]'

This removes punctuation characters.
# 3  
Old 10-21-2008
below script has only three options,
1> only print the digit number
2> only print the alpha
3> only print the special characters

You may amend it to fully address your desire. Hope make sense to you!

a.txt:
Code:
dear,. roopa$#09%~`';'][\.@

Code:
echo "Enter your type: 1[digit],2[alpha],3[special],4[exit]"
read type
if [ $type -eq 1 ]
then
  cat a.txt | sed 's/[^0-9]//g'
fi
if [ $type -eq 2 ]
then
  cat a.txt | sed 's/[^a-zA-Z]//g'
fi
if [ $type -eq 3 ]
then
  cat a.txt | sed -e 's/[0-9]//g' -e 's/[a-zA-Z]//g'
fi
if [ $type -eq 4 ]
then
   exit
fi

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