Shell Programming and Scripting

I am trying to use grep or awk to search for a specific number in a file. For eg.

grep -i "Tag: 140" filename.

The above command also lists other Tag: 140 like below.

Tag: 1409970
Tag: 1409969
Tag: 1409749
Tag: 1409968
Tag: 1409750
Tag: 140
Tag: 1409751
Tag: 1409752
Tag: 1409746
Tag: 1409966

I need only a specific number and not all numbers starting in 140.

Thanks so much.

Use a better regexp to anchor the expression...

Code:

grep '^Tag: 140$' file

assuming that the file has a list of "Tag: Value" pairs and nothing else in it.

Thanks shamrock , i appreciate it.

Yes the file has other information and extra lines and they keep changing , but all i need is to grep for a three digit Tag: number starting with 140. Instaed of listing all lines starting with 140

Tag: 14099 Authority: 87 Status: 0x00 Region: 80
VSR header time: 10-14-2008 13:34:03 SeqNum: 56
Tag: 1406 Authority: 254 Status: 0x00 Region: 70
VSR header time: 10-14-2008 13:37:13 SeqNum: 57
Tag: 14095 Authority: 67 Status: 0x00 Region: 60
VSR header time: 10-14-2008 13:38:38 SeqNum: 58
Tag: 140 Authority: 88 Status: 0x00 Region: 50
VSR header time: 10-14-2008 13:39:15 SeqNum: 59

In your example, you just want to return the last row that starts with Tag:? If so, just include the trailing space in your grep.

based on the example having more stuff after the 140...

Code:

grep "^Tag: 140 " workfile

That worked. I am glad i found this forum. Thanks all again.