Shell Programming and Scripting

I have an awk file where I need to pass a filename and a value as a parameter from a sh script. I need to know how to pass those values in the sh script and how to use the same in the awk file.

Thanks in advance!!!
Geetha

Code:

SHELLVAR=BLA
awk -v awkvar=${SHELLVAR} '{print awkvar}'

If you enter "pass parameter awk" into Google for example, you get tons of useful hits

Thanks zaxxon...

But I am getting error message as,

The file sample.awk,

if (( $14 < ( $13 / ARGV[1] )) && (( $14 > 50) || ( $13 >50 )))
{print}
}

And passing the parameter as,
awk -f sample.awk temp 10

where, temp is the file name and 10 is the value passed.

Now, I received an error message as,
awk: Cannot divide by zero.
The input line number is 1. The file is temp.
The source line number is 1.

Please let me know where I did wrong.

Thanks,
Geetha

Ah ok, parameters - somehow it converted from my eyes to my brain to variables, nvm

Have a look here:
The GNU Awk User's Guide