Shell Programming and Scripting

Hi all
pls help me by providing soln for my problem
I'm having a text file which contains duplicate records .

Example:
abc 1000 3452 2463 2343 2176 7654 3452 8765 5643 3452
abc 1000 3452 2463 2343 2176 7654 3452 8765 5643 3452
tas 3420 3562 2123 1343 2176 7654 3252 8765 5643 3452
aer 1000 3452 2463 2343 2176 7654 3452 8765 5643 3452
tas 3420 3562 2123 1343 2176 7654 3252 8765 5643 3452


I want to compare each and every column of every row with rest columns of file
Im doing by following method:
two for loops
first[$i]=`head -$i filename.txt | tail -1 | cut -d" " -f$num1-$num2`
in same way im extracting entire columns using another foer loop and comparing with "if" condition. Its showing wrong value
can any one help me.
By
G.Aavudai Nayagam.

file <<f1.txt>> will have the data

> cat f1.txt
abc 1000 3452 2463 2343 2176 7654 3452 8765 5643 3452
abc 1000 3452 2463 2343 2176 7654 3452 8765 5643 3452
tas 3420 3562 2123 1343 2176 7654 3252 8765 5643 3452
aer 1000 3452 2463 2343 2176 7654 3452 8765 5643 3452
tas 3420 3562 2123 1343 2176 7654 3252 8765 5643 3452

Code:

below will display the no of occurance and the record
> sort f1.txt|uniq -c
   2 abc 1000 3452 2463 2343 2176 7654 3452 8765 5643 3452
   1 aer 1000 3452 2463 2343 2176 7654 3452 8765 5643 3452
   2 tas 3420 3562 2123 1343 2176 7654 3252 8765 5643 3452

below will display only the duplicate records
> sort f1.txt|uniq -d
abc 1000 3452 2463 2343 2176 7654 3452 8765 5643 3452
tas 3420 3562 2123 1343 2176 7654 3252 8765 5643 3452

below will display distinct records
> sort f1.txt|uniq
abc 1000 3452 2463 2343 2176 7654 3452 8765 5643 3452
aer 1000 3452 2463 2343 2176 7654 3452 8765 5643 3452
tas 3420 3562 2123 1343 2176 7654 3252 8765 5643 3452