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how to grep for a word in a log file..

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# 1  
Old 10-15-2008
how to grep for a word in a log file..
Hi All,

I have a log file which is storing a backup time stamps information in it. (pasted below)

20081006210008 0 20081006211910
20081006222824 0 20081006224758
20081007210049 0 20081007212032
20081008210059 0 20081008212204
20081009210053 0 20081009212801
20081010210142 0 20081010212548
20081011210236 0 20081011212332
20081012210140 0 20081012212507
20081013210351 0 20081013212542
20081014210142 0 20081014212502

Now i would like to grep for last line and display... i know that we can do this using tail -1 |awk {print $1,$2,$3}.

Am using online script for collecting the backup information from all the systems and the problem here is that all the log file are not similar.. some would have spaces at end of the file... so when i do tail -1 it would not work for some of the systems.. and so would have other information at the end of the log file...

since the timestamps are available in all the logfiles... i would like to grep for last line which starts from 2008*.. and i dont know how do we grep for a word which start from 2008 and avoid the remainig when it dont have spaces.

file.log |grep 2008* |tail -1 ... guess this would not work..

How do we do this...?

Guru.. please help..
# 2  
Old 10-15-2008
Code:
grep ^2008 file.log | tail -n1

# 3  
Old 10-15-2008
Thank you... johnson..
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