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Split the access.log based on date

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Top Forums Shell Programming and Scripting Split the access.log based on date
# 1  
Old 10-10-2008
Split the access.log based on date
I am trying to get the content of Apache access.log file for the current date for viewing purposes.
I can get it with the following sed command

sed -n '/09\/Oct\/2008/,/09\/Oct\/2008/p' access.log | less

now I want to enhance it such that it will automatically take current date instead of hard coding. Any ideas will be helpful.

Thanks,
Prathap
# 2  
Old 10-10-2008
man date

You can put it together like
Code:
date +%d #day
date +%b #month, abbrevated
date +%Y #year, 4 digits

To get shell variables into sed, you can just stop sed with ' again, place the variable there, then continue sed with ', like for example
Code:
sed 's/here'${VAR}'something/deleted/g'

# 3  
Old 10-10-2008
grep should be faster
Code:
grep $(date +%d/%b/%Y) file

# 4  
Old 10-10-2008
Yep, that's even better.
# 5  
Old 10-10-2008
Thanks to both of you. Both solutions worked.
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