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ls and egrep together

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# 1  
Old 10-09-2008
ls and egrep together
Hello,
Why is this not returning files containing the string in the var $files?

files=`ls /dir1/dir_level2/dir_level3 | egrep "catch \["`

files=`ls /dir1/dir_level2/dir_level3` this by itself returns a list of files which I thought could be sent through grep or egrep to look for matches.

Can you help me understand?

Thanks.
# 2  
Old 10-09-2008
Does ls /dir1/dir_level2/dir_level3 | egrep "catch \[" return something?
# 3  
Old 10-09-2008
It does not return anything, and I know there are matches for this search .....
Thanks.
# 4  
Old 10-09-2008
The syntax is:

Code:
egrep "catch \[" /dir1/dir_level2/dir_level3/*

Regards
# 5  
Old 10-09-2008
Shouldn't these be equivalent? Yet they are not.
Can anyone explain? thanks.

files=`ls /dir1/dir_level2/dir_level3 | egrep "catch \["`
or even
files=`ls /dir1/dir_level2/dir_level3/* | egrep "catch \["`

files=`egrep "catch \[" /dir1/dir_level2/dir_level3/*`
# 6  
Old 10-10-2008
Quote:
Originally Posted by gio001
Shouldn't these be equivalent? Yet they are not.
Can anyone explain? thanks.

files=`ls /dir1/dir_level2/dir_level3 | egrep "catch \["`
or even
files=`ls /dir1/dir_level2/dir_level3/* | egrep "catch \["`

files=`egrep "catch \[" /dir1/dir_level2/dir_level3/*`
No, they are not. These commands search for a pattern in the filenames:

Code:
files=`ls /dir1/dir_level2/dir_level3 | egrep "catch \["`
files=`ls /dir1/dir_level2/dir_level3/* | egrep "catch \["`

While this command search for a pattern in the files:

Code:
files=`egrep "catch \[" /dir1/dir_level2/dir_level3/*`

Regards
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