Shell Programming and Scripting

Hi to all. I've looked for this, and haven't found it, but please pardon me if I've overlooked something. I'm trying to come up with a relatively simple command line search and replace from and to which I can easily pipe. In particular, let's suppose there are 2 lists, A and B. If a string appears on list A, replace it with its corresponding member on list B. For example, let's replace heroes with villains:

ListA,ListB
Superman,Lex_Luthor
Batman,The_Joker
ProfessorX,Magneto

So, anywhere 'Superman' appears, replace him with 'Lex_Luthor' and so on. So, in a perfect world, 'tr' might be expanded to do this. This doesn't work, of course, so please treat this as pseudocode:

Code:

tr 'Superman,Batman,ProfessorX' 'Lex_Luthor,The_Joker,Magneto'

Something that actually does work is:

Code:

 sed -e 's/Superman/Lex_Luthor/' -e 's/Batman/The_Joker/' -e 's/ProfessorX/Magneto/'

That works, and is an acceptable solution, but will grow pretty quickly with additional terms. Is there a more compact way of accomplishing this? Many thanks in advance.

Iam not sure if these keywords are appearing in a file. Have you tried considering SET command
You need to replace "," by space using "tr"
Read file and each line use can use set command then replace $2 with $1 within a loop ?

the way set works is as
set hi there it is a test
if you echo $3 it prints out "it"
similary as long as there is a space you can print Variables as $1 $2 $3 $4 using set.
Hope this sorts out your problem. Good luck

No, they don't appear in an actual list. I was just using that as a way of picturing what replaces what. In fact, the question that prompted this was that a particular log file uses MON format for the month (that is, spelled-out, first 3 letters, such as Jan, Feb, etc). We needed this to be converted to numeric format, such that Jan becomes 01, Feb becomes 02, and so on. I ended up doing:

Code:

<input> | sed -e 's/Jan/01/' -e 's/Feb/02/' -e 's/Mar/03/' -e 's/Apr/04/' -e 's/May/05/' -e 's/Jun/06/' -e 's/Jul/07/' -e 's/Aug/08/' -e 's
/Sep/09/' -e 's/Oct/10/' -e 's/Nov/11/' -e 's/Dec/12/'`

That worked, but if there's a more convenient and compact way to do this, I'd like to know it.

I had to write the same script in which i had input as number it needed to convert to alphabets. Here is a sample that function .

function r_Keys() {
KeyMap=("0" "Zero" "1" "One" "2" "Two" "3" "Three" "4" "Four" "5" "Five" "6" "Six" "7" "Seven" "8" "Eight" "9" "Nine")
myKey[0]=`echo $1| cut -c 1`
myKey[1]=`echo $1| cut -c 2`
myKey[2]=`echo $1| cut -c 3`
myKey[3]=`echo $1| cut -c 4`
j=0;
for key in ${myKey[@]}
do
for (( i = 0 ; i < ${#KeyMap[@]} ; i=i+2 ))
do
if [ "$key" == "${KeyMap[$i]}" ]
then
roomKey[$j]="${KeyMap[$i+1]}"
fi
done
j=`expr $j + 1`
done
return

Just pass the function any numberal it will return you the equivalent alphabet. Its little complicated but definetly not the compact
Good luck

Here's something you can try if you have Perl and the Date::Manip module installed:

Code:

echo "Jan 24, 2007"|perl -pe 'use Date::Manip;$m=UnixDate(ParseDate($_),"%b");$n=UnixDate(ParseDate($_),"%m");$_=~s/$m/$n/g;'
01 24, 2007

echo "4 Mar 2008"|perl -pe 'use Date::Manip;$m=UnixDate(ParseDate($_),"%b");$n=UnixDate(ParseDate($_),"%m");$_=~s/$m/$n/g;'
4 03 2008