Shell Programming and Scripting

What about this solution in general:

Code:

..... | sed 6,9d 
..... | awk 'NR~"[6-9]"{next}1'

or for the OP request in special:

Code:

.... | sed 5q
.... | awk 'NR==6{exit}1'

... and don't make your life complicated

danmero,
That is exactly what I was look for. Simple and short, I however have not used sed much so was not sure on how to implement it. Thanks for the great tip!

backups01laxint.liuc(s){jsandova}[~]<0>$ nsrjb -v | awk -F' ' '$3>=01{print $0}' | cut -b 1-79 | sed 5q
setting verbosity level to `1'
slot volume used pool barcode
1: intwindows.0005 9% intwindows 010159L2
2: intunix.0009 20% intunix 010155L2
4: intrman.0002 2% intrman 010395L2
24: Cleaning Tape (50 uses left) 000002L1 000002L1

Oops,
it should be:

Code:

awk '!(NR~/^[6-9]$/)'

or:

Code:

awk 'NR~/^[6-9]$/{next}1'

I like this one