Shell Programming and Scripting

Hi people.

I working on a script to check for files that they are suposed not to be on the directory. I mean, inside of each directory it must have some files but some could be wrong, and i want to move the files that are wrong.

Ex:
CSPOTGET edpst/CargadoresSPOT Historicos_Spot_MDI.zip
COBGET edpst/CargadorOmelBroker ??????.xls
CORGET edpst/CargadorOmelReuters CarOmlReuts.xls

On folder " edpst/CargadoresSPOT " must only have " Historicos_Spot_MDI.zip"

On folder " edpst/CargadorOmelBroker " must only have files with " yymmdd.xls" , and no others.

I imagine this "configuration" file where the 1st column is a variable, the second is the directory and the 3rd column is the file(s) of each directory.

Did you understand what i'm wrote?

osramos

You want to find files that DO NOT match the pattern, correct?
ksh allows you to do that:

Code:

#!/bin/ksh
# files that are not named Historicos_Spot_MDI.zip
ls edpst/CargadoresSPOT/!(Historicos_Spot_MDI.zip)
# 
ls edpst/CargadorOmelBroker/!(??????.xls)
#
ls edpst/CargadorOmelReuters/!(CarOmlReuts.xls)

Ok, it works.

But there are almost 50 directories, with some of them with 4 or 5 files to exclude ( not match ).

Can do this with a FOR cycle or something similar?

osramos

What you are asking is to create a resultset that all files minus pattern1 minus pattern2

The only problem for this is that we will have to use grep -v. The file matching patterns become regular expressions

Code:

??????.xls
# becomes regex:
[0-9]{6}\.xls

This will happen for every file you want to exclude. Otherwise, you cannot just

Code:

ls !(pattern)

for five different files because each instance of !(pattern2) will show other patterns like pattern2 pattern3... etc.

Code:

# generalized solution
ls directory | grep -v -e 'regex1' -e 'regex2' -e 'regex3'

Therefore you have to construct 50 different regexes (one for each file you have to specify) and apply some of them to the correct directory output from ls. I cannot do that for you.

Oh, i see.

Another problem i have, assuming i'm using " ls !(pattern) ", is the shell i'm using.

The server is a Windows Server but have installed CYGWIN and Bash doesn't recognize the " ! ".

Is there other solution?

Regards,

osramos