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how to retrieve only the Use% value from df command

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# 1  
Old 09-18-2008
how to retrieve only the Use% value from df command
when I do a df -k for a particular mount i get the result like this

Filesystem 1K-blocks Used Available Use% Mounted on
/dev/ 4128448 3527496 391240 91% /

I need to extract the value 91 from this and use it in my script in an if condition. How will i do it Please advice.
# 2  
Old 09-18-2008
Code:
df -k | awk -F " |%" '/dev/{print $5}'

Regards
# 3  
Old 09-18-2008
Franklin
I tried this one but its not working
its not returning anything
# 4  
Old 09-18-2008
this should work
Quote:
df -k|awk '/\/dev\//{printf("%d",$4);}'
# 5  
Old 09-18-2008

Code:
df | awk '/\/dev\//{printf("%d\n",$4)}'

Or:

Code:
df | awk '/\/dev\//{print $4}'

Or:

Code:
df | awk 'NR > 1 {print $4}'

# 6  
Old 09-19-2008
aah!! johnson the final one works good for me
I am able to get the value using df -k / | awk 'NR > 1 {print $4}' | cut -d "%" -f 1

but is there a more dynamic option than hardcoding $4 ...
thanks for all franklin vidyadhar johnson...
# 7  
Old 09-19-2008
Quote:
Originally Posted by codeman007
aah!! johnson the final one works good for me
I am able to get the value using df -k / | awk 'NR > 1 {print $4}' | cut -d "%" -f 1

You don't need cut; awk can remove the percent sign:

Code:
df -k / | awk 'NR > 1 {sub( "%", "", $4); print $4 }'

Quote:
but is there a more dynamic option than hardcoding $4 ...
thanks for all franklin vidyadhar johnson...

Use a variable for the column:
Code:
n=4
df -k / | awk -v col=$n 'NR > 1 {sub( "%", "", $col); print $col }'

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