## How to perform arithmetic operation on date

How to perform arithmetic operation on date
# 1
How to perform arithmetic operation on date

Hi all,

I would appreciate if anyone knows how to perform adding to date.
As for normal date, i can easily plus with any number.
But when it comes to month end say for example 28 Jun, i need to perform a plus with number 3, it will not return 1 Jul.

 agathaeleanor View Public Profile for agathaeleanor Find all posts by agathaeleanor
# 2
hi,

u can try the following...

expr `date +%d` + 3

subhendu
 subhendu81 View Public Profile for subhendu81 Find all posts by subhendu81
# 3
That specifically does not solve the problem of wrapping at end of month. The FAQ section has a good thread on date arithmetic; see that instead. https://www.unix.com/answers-frequent...rithmetic.html
 era View Public Profile for era Find all posts by era
# 4
Try:

Use date -d as shown below:

Quote:
date -d "\$var days "
Wed Sep 24 00:30:27 IST 2008
var=60
date -d "\$var days "
Mon Nov 17 00:30:37 IST 2008
 dennis.jacob View Public Profile for dennis.jacob Find all posts by dennis.jacob
# 5
simply change TZ to change date..

Test Your Knowledge in Computers #576
Difficulty: Medium
All programming languages have automatic garbage collection that monitors the dynamically allocated pieces of memory and determine if any variable in the program still references it. If the memory is no longer referenced, it is 'garbage' and becomes eligible to be 'collected'.
True or False?

## How to get defined precision after arithmetic operation using syncsort?

I have to do some arithmetic operation on Field 8 which is calculated by Field 9/Field 7 Suppose i have data like : 0800123456|JAN|2017|JAN|2018|0800123456|0|0.0000|0.00| 0800234567|JAN|2017|JAN|2018|0800234567|4|2.5812|10.32| 0800666666|JAN|2017|JAN|2018|0800666666|2|1.7255|3.45|...

## Using awk to do arithmetic operation

Hi, I've this following text file FileVersion = 1.03 Filetype = meteo_on_curvilinear_grid TIME = 0 hours since 2016-10-03 12:00:00 +00:00 -6.855 -6.828 -6.801 -6.774 -6.747 -6.719 -6.691 -6.663 -6.634 -6.606 -6.577 -6.548 -6.519 -6.489 TIME = 0 hours since...

## Arithmetic operation in variable

Hi, Here is the script i try to perform arithmetic operation in two variables . git branch -r | while read brname ; do REV_COMMITS=`git rev-list --count \$brname` echo "\$brname has \$REV_COMMITS" (( TOTAL = TOTAL + REV_COMMITS )) echo "in loop" \$TOTAL done echo "total is " \$TOTAL ...

## Basic arithmetic operation with awk?

input: Name|Operation rec_10|1+2+2- Output: rec_10|1 Basically I am trying to calculate the result of "the path" in \$3 where the operators follow the number and not preceding them like we normally do: rec_10: +1+2-2=1 But I realise (I am sure there is a good reason for that) that awk...

## floating point arithmetic operation error

I am writing a script in zsh shell, it fetchs a number from a file using the awk command, store it as a variable, which in my case is a small number 0.62000. I want to change this number by multiplying it by 1000 to become 620.0 using the command in the script var2=\$((var1*1000)) trouble is...

## Arithmetic operation between columns using loop variable

Hi I have a file with 3 columns. say, infile: 1 50 68 34 3 23 23 4 56 ------- ------- I want to generate n files from this file using a loop so that 1st column in output file is (column1 of infile/(2*n+2.561)) I am doing like this: for ((i=1; i<=3; i++)) do a=`echo...

## Arithmetic operation with awk

I have output like following in a file usmtnz-dinfsi19 72 71 38 1199 1199 0.8 19:23:58 usmtnz-dinfsi19 72 71 38 1199 1199 0.8 19:24:04

## arithmetic operation on two columns

Hi, All, I have a file, its content is as follows: 100 150 120 135 140 170 I want to insert a column, its content is determined by the difference between the two values in the same line, if the difference is less than 20, the new value is 1, otherwise is 0. after the operation, the...

## Help with arithmetic operation

I am using egrep to extract numbers from a file and storing them as variables in a script. But I am not able to do any arithmetic operations on the variables using "expr" because it stores them as char and not integers. Here is my code and the error I get. Any help will be appreciated. #!/bin/sh...

## Simple arithmetic operation

I have no idea why I can't get this to work, if anybody can help i would appreciate it. #!/bin/bash x=`cat counter.txt | wc -l` y= '\$x / 7' printf "%d People have visited this page" \$y :confused: