Shell Programming and Scripting

Hello All,

I want to make a simple script file, that when user run it ./Rutine so all the commands defined in rutine script runs. I am using solaris. and there is one command in it subshl which changes the prompt from # to < and then i have to run commands for that < prompt like this < rcv:menu;

#subshl
USLI TERMINAL IN SERVICE.
<

Code:

the command in script is:
df -k
Mirrors
DisplayAll
subshl
rcv:menu;

The problem is this that all the commands upto subshl runs and < prompt opens but the commands of < prompt dont runs.

Actually the question is that how to make script which open subshl prompt <
and runs command for it defined in script.




Regards,
Waqas Ahmed

In order to change the prompt, the script must be run in the same environment. Executing a script runs the command in a child process and cannot change the calling environment.

To change the prompt, you must source the script, not execute it, e.g.:

Code:

. ./Rutine

Making it simple, I want to run these two commands through script

Code:

#!/bin/sh
subshl
rcv:menu;
exit

Problem is this that subshl command run and subshl prompt opens and prompt cahnges to this < but command: rcv:menu; dont run.

WHY ??

Please help to solve this problem.

Regards,
Waqas Ahmed

Yes below code is working :

Code:

printf "%s\n" "rcv:menu;" exit | subshl

But now the problem is this that script hangs after output. and it also dont allow to do anything. to exit from subshl prompt we use "quit;" command.

Second after the output of first commands how i enter line for second command
is it like this:

Code:

printf "%s\n" "rcv:menu;" exit | subshl
printf "%s\n" "op:version;" exit | subshl
printf "%s\n" "quit;" exit | subshl

I tried this :

Code:

printf "%s\n" "rcv:menu;" exit | subshl
printf "%s\n" "quit;" exit | subshl

but it only gives first command output and second one dont works!

??

Regards,
Waqas Ahmed

Thanks Alot !!!

Regards,
Waqas Ahmed