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Shell Programming and Scripting

Script to find string and return next 2 lines

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# 8  
Old 10-09-2008
Hammer & Screwdriver A strange appraoch; but appears to give desired results
Although my main command seems to do a lot of substitution, it does provide the next two lines of text after the line containing "query"

Code:
> cat file4
msj
mh
query
return this 1
return this 2
mjk
mhj
query
return this 3
return this 4

> sed "s/^query/~query/" file4 | tr "\n" "#" | tr "~" "\n" | grep "^query" | cut -d"#" -f2-3 | tr "#" "\n"
return this 1
return this 2
return this 3
return this 4
>

# 9  
Old 10-09-2008
It seems like grep should be able to do this. If we call your datafile "data.file", you should be able to do something like:

Code:
grep -A 2 query data.file

If you want to exclude the actual matching line, just do:

Code:
grep -A 2 query data.file | grep -v query

I haven't tested it, but it seems it should do just what you need.
# 10  
Old 10-09-2008
Code:
awk '/query/{getline; print; getline; print}' filename

# 11  
Old 10-09-2008
Quote:
Originally Posted by daveaasmith
...
I want the lines after (and including) "Statement", up to (not including) "Stack Trace". There may not always be the same number of lines between the two.

(Example File)
Statement Execution Time
Select Distinct.......
From.........
Where..........
Order By........
Stack Trace
config.java.feeds.invoices

Or you can use flags:


Code:
awk '/Statement Execution Time/{f=1}/Stack Trace/{f=0}f' file


Output:

Code:
Statement Execution Time
Select Distinct.......
From.........
Where..........
Order By........
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