Shell Programming and Scripting

Hello All,

As explained above, i am also into similar issue

Brief on the issue (PS:* used below is nothing but space):

If i execute the below command on the command line:
date +'%b %e'
Output is: Nov 5 [Nov**5]

but when i am trying to store this into a variable as below inside a script:

set dt = `date +'%b %e'`
echo "$dt"


and then run the script (.csh)

Output: Nov*5


Required output from the script should be Nov**5


can some one help on this.....

thanks a ton in advance....cheers.

Try set dt="`date +'%b %e'`".

Hiii

date "+%b %e"

The command can be used in any grep statement instead of storing it in a variable ..like the below one

grep "$(date "+%b %e")"

with the command -> date "+%b %e"
Output: Nov 6

the commands provided in the didnt work

ls -ltr | grep 'date "+%b %e"'
ls -ltr | grep '(date "+%b %e")'
ls -ltr | grep '$(date "+%b %e")'

ls -tlr | grep "$(date "+%b %e")"
Error: grep: can't open %e)


but if i execute:
ls -ltr | grep 'Nov 6'

i get the required output.

any other inputs ?

This work for me:

Code:

ls -ltr | grep "$(date '+%b %e')"

..maybe you need:

Code:

ls -ltr | grep "$(date '+%b%e')"

As Ajay discovered, some shells don't cope well with nested double quotes, even though the $( ... ) should have higher precedence, so it's not a safe syntax to use.

The patter in grep must always be enclosed in double quotes.
try that..