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Prase a file and stored the result to an array

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# 1  
Old 09-03-2008
Prase a file and stored the result to an array
Dear all ,

I have a file whose content has the following format:

jboss.web:type=ThreadPool,name=AAAA
jboss.web:type=ThreadPool,name=BBBB

How can I parse this file to get the value of the name of each line (AAAA , BBBB) and store the result to an array ? (array[0] = AAAA , array[1] = BBBB).
Different files will have different total number of lines.

Regards.
# 2  
Old 09-03-2008
What programming language you are using?
# 3  
Old 09-03-2008
You can do something like:

Code:
#!/bin/sh

cnt=0

awk -F"=" '{print$3}' file | while read name
do
  arr[$cnt]=$name
  let cnt=cnt+1
done

Regards
# 4  
Old 09-03-2008
code:
sed -e 's/'^.*='/ /g' filename |awk '{print NR ,$1}'
or
sed -e 's/'^.*='/ /g' filename

this helps u. use in ur for loop
# 5  
Old 09-03-2008
Try using the below in a loop to assign in an array:

Code:
sed 's/\(.*\)name=\(.*\)/\2/' file

or

Code:
while read line; do echo ${line#jboss.web:type=ThreadPool,name=}; done<file

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