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How to fetch variable value in if block and to compare it with certain string

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# 1  
Old 08-30-2008
How to fetch variable value in if block and to compare it with certain string
Hi,

I am trying to execute this command

if [ `$exception_info | grep "Exception if any" > /dev/null 2>&1; echo $?` -eq 0 ]; then

but getting error .Some problem with reteriving the value of $exception_info.
Please help.Its urgent.

thanks
# 2  
Old 08-30-2008
try this..
Quote:
if [ `echo "$exception_info"|grep -w "Exception if any" > /dev/null 2>&1; echo $?` -eq 0 ]; then
# 3  
Old 08-30-2008
not working
Its skipping this if block. Smilie
# 4  
Old 08-30-2008
Quote:
Originally Posted by khushboo
Its skipping this if block. Smilie
run your script as sh -x scriptname
then post the out put..
# 5  
Old 08-30-2008
worked :)
hey thanks a lot.It worked ,i was not using double quote thts why i was getting the error.

thanks
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