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Unix code to fetch the first field till space in a variable

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# 1  
Old 08-27-2008
Unix code to fetch the first field till space in a variable
Hi,

I want to get the value of the first field till space in a variable.

e.g x=323 /test/personel/logs/File1 [After 3 space is there]

I want to get the first field till space i.e 323 in another variable ,lets say y.

echo $x|cut -d' ' -f1 gives 323
but when I'm trying y=`echo $x|cut -d' ' -f1 its giving error.

Please help.
# 2  
Old 08-27-2008
Hi! to be sure, since your value has a space in between them, enclosed them with a double quotes, like this:
Code:
x="323 /test/personel/logs/File1"

In your command substitution(using backticks), I don't know if it's a typo or what? But it should be written as this,
Code:
y=`echo $x|cut -d' ' -f1`

# 3  
Old 08-27-2008
y=`echo $x|awk '{print $1}'`
# 4  
Old 08-27-2008
It's both safer and more efficient to use the shell's built-in variable substitution syntax.

Code:
y=${x% *}

To be sure, echo $x without double-quoting the variable name $x will wreck the whitespace in the variable's value.
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