Shell Programming and Scripting

Hi Friends,

REQUIREMENT: Want to delete files from the current directory match with the same in the file test.txt

set -x
i=1
echo "i=$i"
COUNT=`sed -n '$=' test.txt`
echo "Count=$COUNT"
while [ $i -lt $COUNT ]
do


"## Here is error##"
FILETOREMOVE=`sed -n \'$i,1p\' test.txt`


echo $FILETOREMOVE
rm -f $FILETOREMOVE
i=`expr $i + 1`
done

Please let me know what is right way to assign value to a variable with rows(using -n) returned by sed?

It's not necessary you use sed, this should do the job:

Code:

while read file
do
  echo "$file"
#  rm -f "$file"
done  < test.txt

Try it first with echo to be sure you get the right output.

Regards

Hi Franklin,

Thank you for the new concept. I will sure use that in future....

However I will still love to know how to assign the values to variable in returned the the form of row from sed as I mentioned in my thread.

Here assignment operator "` `" was not working . What should be the right syntax to do it ? It might be useful to know..


Thanks

Replace single quotes by double quotes :

Code:

FILETOREMOVE=`sed -n "${i}p" test.txt`

You can use wc command instead of sed in the COUNT calcul :

Code:

count=`wc -l test.txt`

.

The best way to do the work is Franklin's solution.

Jean-Pierre.

Take a look at this example of variable assignment:

Code:

> ls file*
file1  file2  file3
> filecnt=$(ls file* | wc -l)
> echo $filecnt
3

Rather than the ` backticks, using the $(...) seems to be a little cleaner to execute and read. Perhaps modify your variable assignment similarly?

Hi Aigles,

It is working Perfectly...

@Joeyg,

$(..) already had tried but didn't work...

But don't know why it worked with COUNT=`sed -n '$=' test.txt`.....

Thanks