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check if a directory exists if not make it

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# 15  
Old 08-24-2008
If i do that i get syntax error unexpected token 'then'

ahh this is driving me nuts it was working before!

Code:
if [ -d /tmp/old ]
then
echo "DIR exist"
else
echo "Error: '$check' does not exist!!"
echo "EXITING"
exit 1
fi

# 16  
Old 08-24-2008
Code:
[ -d /tmp/old ] || echo "not found"

# 17  
Old 08-24-2008
Quote:
Originally Posted by aigles
Replace elif by else.
A comment is not evaluated as an statement, she shell will signal a syntax error on the else line. A null statement is specified with ':' :
Code:
if [-d /tmp/old]
then
   : #do nothing
else
   echo "directory exists"
   exit 1
fi

You can also invert your test :
Code:
if [! -d /tmp/old]
then
   echo "directory exists"
   exit 1
fi

Jean-Pierre.
Sorry, There are missing spaces in the if tests :
Code:
if [ -d /tmp/old ]
then
   : #do nothing
else
   echo "directory does not exist"
   exit 1
fi

Code:
if [ ! -d /tmp/old ]
then
   echo "directory does not exist"
   exit 1
fi

Jean-Pierre.
Last edited by aigles; 08-24-2008 at 12:54 PM.. Reason: Oops ! Message correction (thanks era)
# 18  
Old 08-24-2008
"If not directory /tmp/old then echo directory exists"? I think you got that backwards.

If the topic title of this thread is any indication then mkdir -p /tmp/old is all that's needed. If the directory exists, nothing happens. If it doesn't exist, it's created.
# 19  
Old 08-25-2008
mkdir /tmp/old 2> /dev/null

if is there. it will do nothing
if its not there. it will creat it.
# 20  
Old 03-25-2009
if [ -d /tmp/old ];
then
echo "DIR exist"
else
echo "Error: '$check' does not exist!!"
echo "EXITING"
exit 1
fi

Above will work try now
# 21  
Old 03-25-2009
Will "if [[ -d /tmp ]]" do any good here? just curious...
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