Shell Programming and Scripting

Dear friends,

I receive the following files into a FTP location on a daily basis

-rw-r----- 1 guest ftp1 5021 Aug 19 09:03 CHECK_TEST_Extracts_20080818210000.zip
-rw-r----- 1 guest ftp1 2437 Aug 20 05:15 CHECK_TEST_Extracts_20080819210000.zip
-rw-r----- 1 guest ftp1 3564 Aug 21 05:30 CHECK_TEST_Extracts_20080820210000.zip
-rw-r----- 1 guest ftp1 1410 Aug 22 05:22 CHECK_TEST_Extracts_20080821210001.zip

From the above listing, it shows
On Aug-21, we receive file dated 20080820
On Aug-22, we receive file dated 20080821
Which means on a particular day, we will always receive extracts dated [current date -1] i.e previous day suffixed file.

Can you please provide unix command , which will achieve the following:
1] Unix command which when invoked today should pick up a file from above location based on date-suffix logic [current date -1] , i,e it should pick up file dated 21-Aug,,,1.e CHECK_TEST_Extracts_20080821210001.zip when invoked on 22-AUG-2008

2] Unix command , which will identify all the files FTped on a particular day and move them to another location.

For ex: if 2 files are FTPED today as follows:
-rw-r----- 1 guest ftp1 3564 Aug 22 05:30 CHECK_TEST_Extracts_20080820210000.zip
-rw-r----- 1 guest ftp1 1410 Aug 22 05:22 CHECK_TEST_Extracts_20080821210001.zip

Then command should identify these 2 files as received today [22-AUG] and move them to another location

Please advice

Thanks in advance...........
Regards,
Suresh

can you post the result of

CAn some one please reply ?