Shell Programming and Scripting

Hi
I want the 'ls' command to display only the file size,date modified and name of the file.What i could see with different options is this:

$ls -got packagecount.csv
$-rwxrwxrwx 1 393137 Aug 21 14:46 packagecount.csv

Now what should be my possible combinations,so that i can get this:
393137 Aug 21 14:46 packagecount.csv
Is there any other options to go for it?

Best Regards
Shovan

i think you have to use this..
ls -got filename|awk '{print $3 $4 $5 $6 $7}'

Check if you can get any options in man page.

- nilesh

If the filename consists of spaces then your command will not work properly...

Hi,
Thanks guys for so many reply.Indeed it worked.But what if i want to give the file as a source from the find command result.How would i do this?
b="directory where i am looking for the file
a=file to which i am writing the output
abc_*.package is the pattern i am looking for

I am new to scripting,and sorry for any silly questions,i can find the output and post it to destination using:

find $b -name \*abc_*.package -exec ls -goth '{}' \;>>a

So i am getting the files with entire path being enlisted.Now i observe "sed" can be used or can i use awk'{print $3 " " $4 " " $5 " " $7}'.But i am not sure about how to do this.I am not comfortable at redirection.

Best Regards
Shovan