Shell Programming and Scripting

Hi there all,

I am trying to build a script that will e-mail me a warning when 1 of the HD reaches over 90%
I got it working so far a that it mails me when it reaches a **% with an if statement.
so if [ "$PKG" = "90%" ]
but is there a way to get the % out of the variable?
I get it with
PKG=`bdf /***/*** |grep "***" |awk '{printf $5}'`
so than I can make it
if [ "$PKG" = > "90" ]
Well that's what I think.
But I dont know that much.
or is there an other way to get this working?
I dont want to make a than for every 90% + (so 90%, 92%, 93%, and so on)

thanx in advance people!

PKG=`bdf /***/*** |grep "***" |awk '{printf $5}' | tr -d '%'

A MILLION Thanx!
And thanks for the fast reply.

But now I come on the next problem.

Now I got that if statement
if [ "$PKG" = "90" ]
but how can i make it that if $PKG is 90 or higher, that he runs the script?
Becouse now it only checks if it's 90.

Thanx again in advance!!

df -h | awk '{printf $5 "\n"}' | tr -d '%',[a-z] | awk -F, '($0 >=90) {print "warning " $0}'

hmm that line isnt working.
The -h command is not known

I'm working on a HPUX L2k
But isnt there a way to make the statement for an if that it checks grater than? with a simple >
Thanx!

PKG=`bdf /***/*** |grep "***" |awk '{printf $5}' | tr -d '%',[a-z] | awk -F, '($0 >=90) {print "warning " $0}'