Shell Programming and Scripting

Hi Friends
I am facing some problem in extract the lines between two fixed lines
for examplemy text file look like ...

--------
line 1
line 2
line 3
---------
line 4
line 5
--------
line 6
line 7
line 8
line 9
line 10
---------

now i want the data between "-------" these lines and store the data between each block in diffrent varaible.

Sushant

What have you done to attempt to solve this problem yourself?
Post your sample script, and we'll see how we can assist.

Regards

i would probably read the file line by line, and inside the while , i would use one or more fis to identify th content of the line.
based on that, take the actions you want with that data.
you could use temporal files, which is easier to work with when you dont know the amount of data blocks, and dont know how many variables you will need to hold that data

I forget to tell that i also know the one line before and after "-------------"
so for that i simply use
sed -ne '/line1/,/line3/p' file name
but i am facing one problem in thats
there is very little diffrence between each before and after statement like this

Runing Test Case LS01
...........
...........
Test Case LS01 Completed
----------------------------

Runing Test Case LS01_A
.................
.........
Test Case LS01_A Completed
----------------------------

Runing Test Case LS02
...............
..............
Test Case LS02 Completed
----------------------------

now if i run the above command like this
sed -ne '/LS01/,/LS01/p' file_name
than its show both block LS01 and LS01_A but i want only LS01

Thanks for helping me
Sushant

try below perl script

Code:

$file=shift;
$del=shift;
print $file,"----",$del,"\n";
open(FH,"<$file") or die "Can not open file";
$n=0;
while(<FH>){
        if((index $_,$del)!=-1){
                print $_;
                $arr[$n]=sprintf("%s%s",$arr[$n],$_);
        }
}
close(FH);
for($i=0;$i<$#arr;$i++){
        print $arr[$i];
        print "******************\n";
}