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Shell Programming and Scripting

Parsing char string

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# 1  
Old 08-07-2008
Tools Parsing char string
I am stumped! I need to parse an input parameter to a script that has the form '-Ort'. I basically need 'O', 'r' and 't', i.e. the individual characters in the string parsed.

Since there are no delimiters, I don't know how awk could do this. Can someone tell how to do this, this should be a common task in writing scripts?
ALTRUNVRSOFLN
# 2  
Old 08-07-2008
Tools Does the following help?
Code:
> echo '-Ort' | awk '{print substr($0,2,1)}'
O
> echo '-Ort' | awk '{print substr($0,3,1)}'
r
> echo '-Ort' | awk '{print substr($0,4,1)}'
t

# 3  
Old 08-07-2008
Another Ways (get second char) :
Code:
echo '-Ort' | cut -c2  
expr substr '-Ort' 2 1

Jean-Pierre.
# 4  
Old 08-07-2008
Code:
echo '-Ort' | awk -F\- '{gsub(".","&\n",$2);printf("%s",$2)}'

# 5  
Old 08-07-2008
if you are parsing the argunments send by you in a script. like
./yscript.sj -orT

the you could use getops
Getopt and getopts
# 6  
Old 08-07-2008
Or this one
Code:
echo '-Ort' | awk 'BEGIN{FS=""}{for(i=1;i<=NF;i++)if($i ~ "[a-zA-Z]"){print $i}}'

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