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shell script Variable

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# 1  
Old 08-07-2008
Bug shell script Variable
hi all,

i want use the variable value as a new variable name. And i want to use this new variable value


for i in COMPUTER1 COMPUTER2
do
flag_name=${i}_FLAG
eval ${flag_name}=123
echo $i'_FLAG'
done

output is
COMPUTER1_FLAG
COMPUTER2_FLAG

i need output as 123
# 2  
Old 08-07-2008
You need an eval around the echo too. And a literal dollar sign in front of the variable.

Code:
eval echo \$${i}_FLAG

It will print 123 twice, of course, when the loop runs twice.
# 3  
Old 08-07-2008
Its Working. Thank U Smilie
# 4  
Old 08-07-2008
having problem with if condiation
hi era,

your given code (eval echo \$${i}_FLAG) is woking fine.

now i want to use the variable value to in if condiation..
is following code is right. please help


for i in COMPUTER1 COMPUTER2
do
flag_name=${i}_FLAG
eval ${flag_name}=1
if [ `eval echo \$${i}_FLAG` -eq 1 ]
then
echo yes
else
echo no
fi
done
# 5  
Old 08-07-2008
With the backticks, you will be requiring even more backslashes. But I'd recommend against using backticks, and "if test -eq".

Code:
eval 'case $'${i}'_FLAG in 1) echo yes;; *) echo no;; esac'

Last edited by era; 08-07-2008 at 03:24 AM.. Reason: Oops, fix quoting
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