Shell Programming and Scripting

Hi,

I have a first shell script (/bin/sh) that receives some paremeters. This is only an example (there are more parameters in fact and this one is among them):
-header "This is a test"
This script calls a secund shell script (/bin/sh) with the same parameters. But, quotes disappear as I would expect it unluckily...
This is the first script:

Code:

#!/bin/sh
 echo "mytest.sh"
 parameters=$@
 while [ $# != 0 ] ; do
     echo $1
     shift
 done
 ./mytest2.sh ${parameters}
 exit 0

This is the secund script:

Code:

#!/bin/sh
echo "mytest2.sh"
while [ $# != 0 ] ; do
    echo $1
    shift
done
exit 0

The result is:

Code:

{velo_love}69: ./mytest.sh -header "This is a test"
mytest.sh:
-header
This is a test
mytest2.sh:
-header
This
is
a
test

So, how to pass the parameter between quotes from the first script to the second one? Any tips?

Best regards,


[EDIT]
Ok, I think I have found something interesting. If I change my first script into this

Code:

#!/bin/sh
echo "mytest.sh:"
./mytest2.sh ${1+"$@"}
exit 0

Then all parameters are correctly passed between the two scripts:

Code:

{velo_love}239: ./mytest.sh -header "This is a test"
mytest.sh:
-header
This is a test
mytest2.sh:
-header
This is a test