How to get Previous date in this format.


 
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# 1  
Old 07-22-2008
How to get Previous date in this format.

hi ,

I am using this to get previous date :

#!/usr/bin/ksh
date '+%m %d %Y' |
{
read MONTH DAY YEAR
DAY=`expr "$DAY" - 1`
case "$DAY" in
0)
MONTH=`expr "$MONTH" - 1`
case "$MONTH" in
0)
MONTH=12
YEAR=`expr "$YEAR" - 1`
;;
esac
DAY=`cal $MONTH $YEAR | grep . | fmt -1 | tail -1`
esac
echo "Yesterday was: $MONTH $DAY $YEAR"
}
Output : 07 21 2008

i want output as Jul 21, not as 07 21, can someone help me out.

Thanks
# 2  
Old 07-22-2008
How about:
Code:
$ date -d "yesterday" +"%b %d %Y"
Jul 21 2008


Last edited by BMDan; 07-23-2008 at 11:16 AM.. Reason: Misread which month encoding you wanted
# 3  
Old 07-22-2008
YESTERDAY=`TZ=GMT+24 date "+%m %d %Y"`
# 4  
Old 07-22-2008
If you are using ksh93
Code:
$ printf "%(%b %d)T\n" "yesterday"
Jul 21
$

# 5  
Old 07-23-2008
TZ=GMT+24 date "+%b %d %Y"

Jul 22 2008
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