Shell Programming and Scripting

Hi

I am trying to move older files from adirectory to a archived folder. and I get the error "sh: /usr/bin/find: 0403-027 The parameter list is too long.". The following commnads is being used:

find /dir1/dir2/dir3/dir4/dir5/* -prune -type f -mtime +2 | xargs -l50 -i mv -f {} /dir1/dir2/dir3/dir4/dir6/

The source folder has around 6000 files. Approximately 2000 files per day. We would like to keep 2 days old files only.

Is there any other way this can be done?

Thanks,

Try:

Code:

find /dir1/dir2/dir3/dir4/dir5 -type f -prune -mtime +2 | xargs -l50 -i mv -f {} /dir1/dir2/dir3/dir4/dir6/

There's no need to specify '*' when find is quite capable of locating the files itself.

The error has disappeared but this command is picking up files from the subdirectories under dir5 as well. I want to archive only the files from currnet directory i.e. dir5.
I have made a slight change to the command. The target directory happens to be a subdirectory under the current directory.
How do I mdofiy this to pick up files from current directory only.
find /dir1/dir2/dir3/dir4/dir5 -type f -prune -mtime +2 | xargs -l50 -i mv -f {} /dir1/dir2/dir3/dir4/dir5/dir6

Sorry, should have realised that.

Try this:

Code:

find /dir1/dir2/dir3/dir4/dir5 -type d -a ! -name dir5 -prune -o -type f -mtime +2 | ...

Thanks for the quick response. Unfortunately this also did not work. It listed the subdirectories only.

I'll get there in the end. :-)

Code:

find /dir1/dir2/dir3/dir4/dir5 -type d -a ! -name dir5 -prune -o -type f -mtime +2 -print | ...

This one did not list anything.