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Please help: Build a sed command and execute it in a script

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Top Forums Shell Programming and Scripting Please help: Build a sed command and execute it in a script
# 8  
Old 07-18-2008
Quote:
cat test1.txt | $($sedcmd) > temp2.txt

where sedcmd = sed -n '/08465696_1215781522540/,/70225547_1215781581748/p'

I don't get an output in the temp2.txt. When I run the script in debug it states 'No such file or directory'
Firstly, you're not going to get any output in temp2.txt because you are passing "-n" which suppresses output.
Secondly, I'm still trying to figure out why you can't run a command when the command is stored inside a variable. sed seems to be executed, but it can't make sense of what I pass in. If I run sed from the command line with the same arguments, it works fine.
Last edited by cooldude; 07-18-2008 at 11:32 AM..
# 9  
Old 07-18-2008
Thats exactly what I get. When I run the command on the command line it works but not with the script. the /p at the end prints the range withinn. If you run the command it does produce an output.
# 10  
Old 07-18-2008
Not to hijack this topic, I've had problems like this before, except that I was passing variables to scripts, i.e.,
Code:
asdf="\( -name '*.hh' -o -name '*.cc' -o -name '*.c' \-o -name '*.h' \)"
find /usr $asdf

find, not the shell script, throws an error:
Code:
find: paths must precede expression

When I use the string and not the variable in the script, find works. I searched around, and I could not find an answer.
I've tried:
Code:
asdf="\( -name '*.hh' -o -name '*.cc' -o -name '*.c' \-o -name '*.h' \)"
or
asdf="\\( -name '*.hh' -o -name '*.cc' -o -name '*.c' \-o -name '*.h' \\)"
or
asdf="( -name '*.hh' -o -name '*.cc' -o -name '*.c' \-o -name '*.h' )"
or
asdf="( -name '*.hh' -o -name '*.cc' -o -name '*.c' \-o -name '*.h' )"
or
asdf="-name '*.hh' -o -name '*.cc' -o -name '*.c' \-o -name '*.h'"

Same results. I've been using python more recently.
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