Need to print certain lines from a file


 
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# 22  
Old 08-04-2008
Hi
I have a request. I need to print 50 lines from a file from a certain point within the file. I will be looking for the word 'exception' within the log file and once I find it, I would like to print the next 50 lines from that point onwards (including that line). Can anyone please help me in this regard.
# 23  
Old 08-04-2008
I did try this.
awk 'c&&c--;/Exception/{print NR;c=10}' logfilename.log

But, I am getting the below errors.
awk: syntax error near line 1
awk: bailing out near line 1
# 24  
Old 08-04-2008
It is bad etiquette to hijack someone else's thread, you should start your own unless the question is related.
# 25  
Old 09-29-2008
shell programming

Hi All,

How to compare lines from file with files under one directory..
example

i have file called test,in that i have .dbf files

/u01/test/system.dbf
/u01/test/undo.dbf
.....
.....

and i have directory..
/SID/oradata/

under this directory i have .dbf file

system.dbf
undo.dbf
....
....


i need to compare both the things and if it missmatches ,
then i need to replace .dbf files under directory with that file .dbf file.


Please hlep me.

Thanks
Jack
# 26  
Old 09-29-2008
You should create a new thread for a new question.
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