Shell Programming and Scripting

Hello,

Need some help here. I have this script (test.sh):

#!/bin/sh
var=$1
(( var = 2 * var ))
echo $var

Now I want to call this script from awk with one argument and then capture the result in a variable, something like:

echo 40 | awk ' { x = $1; "test.sh " x | getline y; print y } '

In this case, instead of the result (80 = 40 * 2), I receive the following error message:

sh: 40: command not found

My real problem is of course more complicated but this is the only problem I need to solve to have it working. I dont want to save the result of test.sh in a file (for example using system) and them read it into y with getline, I want just to pipe the result. Is this a problem with sh?

Thanks in advance

I could find the answer in other post. Need to do:

echo 40 | awk ' { comm="test.sh "$1; comm | getline y; close(comm); print y } '

Is a nice trick