Shell Programming and Scripting

Dear All,
Could you please help me to split a file contain around 240,000,000 line to 4 files all equally likely , note that we need to maintain that the end of each file should started by start flage (MSISDN) and ended by end flag (End), also the number of the line between the start flag (MSISDN) and end flag (End) are variable.
Kindly find below sample of the lines in the file
//////////////////////////////////////////////////////
MSISDN
line1
line2
line3
line4
line5
.
.
Line36
End
MSISDN
line1
line2
line3
line4
line5
.
.
line37
End
MSISDN
.
.
//////////////////////////////////////////

Thank you in advance,

If you have not known about the split command, then please have a look

Code:

man split

I hope you may need to use the -l option.

This should prints the sections into file1, file2, file3 etc.:

Code:

awk '/MSISDN/{i++}{print > "file"i}'  file

Regards

Dear krishmaths,

many thanks for ur relpy, unfortunately split command will not be helpfull as the source file has records and each record has lines started by MSISDN flag and Ended by End flag, but split command split the files base on number of lines or by bytes.

Dear Franklin52,

Thank u for ur reply,my input file has more than 6,000,000 record ,which is mean the awk will output 6,000,000 file,my request only to split the file into 4 or 5 files.

Thank u again and waiting ur valuable contributions

Not true, the awk command creates files by sections between "MSISDN" and "End". How do you want to seperate the output in 4 or 5 files? How many sections in 1 file?

Regards

the number of sections in the input file (large file) are 6,000,000 section, so what i need is splitting this file to 4 or 5 files with maintaining that the section start and end in each file.
Thanks,