I have written a Shell Script Program which accepts 3 parameters as shown below:
in the above line ./calc is the Shell Script itself with 3 parameters, namely:
20
+
and 2.
Well, now let's look inside the Script:
The output will be as per our expectation:
But well, let's change the sign in the 2nd parameter being passed:
All those there examples have no issues so far!
But when we pass * as a parameter
things go bad!
Instead of *, the result of "ls *" command or simply the directory list gets passed to the variable: $2.
So, how can I make this Calculator program a user friendly one? I have been suggested to use '*' (I have not tried it yet, however) but it doesn't seem to be a User Friendly Way of writing any script or program, does it?
try
and you'll get a ls listing again. Escaping the asterisk only seems to work on numerals. Does anyone know a workaround?
If typing an extra command before & after you're done using the 'calc' utility is acceptable, you could type "set -f" first... ("set +f" to set it back when you're done)...
(Unfortunately, putting this command inside your script won't work, since by the time the script is executed, the * special character will already be expanded...)
One thing you might try is using the double parens math workings of bash. Quite cool and is readable, and it avoids your shell expansion problem. Secondarily, a "here" document with the "dc" program is how I used to do it. e.g.:
dc <<EOF
2 20 * p
EOF
will produce 40 as output
Using the double-parens syntax of bash, one can do this:
$i=0
((i=2*20))
echo $i <-- produces 40
Kinda cool, huh?
Last edited by fsahog; 07-18-2008 at 11:47 PM..
Reason: To illustrate more fully
Hi ,
I am passing date parameter through file
my shell script testing.sh is
#set -x
#set -v
asd=$1
asd1=$2
echo $asd
echo $asd1
Passing parameter as below
sh testing.sh `cat file1.txt`
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one_2two
one_3two
if
then
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exit 0
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#include <stdio.h>
#include <stdlib.h>
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