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How to get the position of a file

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# 1  
Old 07-07-2008
How to get the position of a file
hi '

$ ls -ltr
total 72
-rwxr-xr-x 1 staff 89 Jan 5 2008 STG_FCT__TYPE.dat
-rwxrwxrwx 1 staff 28 Jan 5 2008 STG_FCT_LINE_SUMMARY.dat
-rwxrwxrwx 1 staff 377 Jan 5 2008 STG_FCT_dd.dat
-rwxrwxrwx 1 staff 7328 Jan 5 2008 STG_FCT_FLAT_FILE.dat
-rwxrwxrwx 1 staff 480 Jan 5 2008 STG_FCT_aa.dat
-rwxr-xr-x 1 staff 1839 Jan 5 2008 STG_FCT__gd_LINE.dat
-rwxrwxrwx 1 staff 413 Jan 5 2008 STG_FCT_def_REP_LINE.dat
-rwxrwxrwx 1 staff 60 Jan 5 2008 STG_FCT_abc_TYPE.dat

how will i get the position on second file like STG_FCT_LINE_SUMMARY.dat only

means i want to save the contents of file second in one variable but the name of the file changes so i have to give some generic type command to find the position of second file.



# 2  
Old 07-07-2008
Hammer & Screwdriver Use a 'head' and 'tail'
The following will show you only that line. (Beware, you need to grab the thrid line since there is that 'total 72' as the first line.)
Code:
ls -ltr | head -3 | tail -1

This will give you only the filename
Code:
ls -ltr | head -3 | tail -1 | tr -s " " | cut -d" " -f9

# 3  
Old 07-07-2008
thanks it work
# 4  
Old 07-07-2008
One more way --

ls -ltr | sed -n '3p' | awk '{print $NF}'
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