Shell Programming and Scripting

from the command line
ls *
output

filename1 filename2 filename3 filename4

directory1:
bashScript1 bashScript2 bashScript3

directory2:
ShellScript1 ShellScript2 ShellScript3

directory3:
C++1 C++2 C++3
___________________________________________________
In my script i want when i do ./test * does the same

filename1 filename2 filename3 filename4

directory1:
bashScript1 bashScript2 bashScript3

directory2:
ShellScript1 ShellScript2 ShellScript3

directory3:
C++1 C++2 C++3


Sorry, i couldn't post my script because im on windows environment, but in case still want me to paste the code, i'd switch to linux.

Thanks.

Well, ls "$@" inside your script should have that effect.

unfortunately didnt work, thats what ive done

'*')

ls "$@"
;;


d)

clear
echo " "
test -f $FileName #check if the name of directory is a valid file
if (($?==0))
then
echo "you have file the same name"
else

test -d $FileName
if (( $? == 0 ))
then
echo "Directory \"$FileName\" allready exist, you are not allowed with overwriting a direcotry."
else
echo " . "
echo" Folder being created..."
sleep 1
echo " . "
sleep 1
mkdir $FileName
chmod 740 $FileName
clear
echo "New Directory \"$FileName\" has been creacted with the following:"
OutputInfo $FileName;
fi
fi
;;


have i missed anything, or where im wrong !!
Thanks.

Your case statement will never match '*', because the calling shell replaces '*' with the matching filenames when you run your script (as I said in my first response).

You would have to turn off globbing in your shell (set -o noglob) before running your script, or else run it using scriptname '*'.

As zaxxon said, it seems kind of silly to write a script to do what ls does perfectly well on its own?

To help you understand what I'm saying, try typing this:

echo *

and this:

echo '*'