Shell Programming and Scripting

Hi,
probably a newbie question..... But there it goes.

I have a list words. This list is taken out of a file with grep and cut.
my @system = (`grep up system_list| cut -d':' -f1`
);

system=
sm00xp03
sm01ftp02
sm00ssh12

What I want to have is a list, with each of the words in the first list changed and resulting in two words, like this

new_list=
sr00xp01
sr00xp02
sr01ftp01
sr01ftp02
sr00ssh01
sr00ssh02

The chars that aren't in bold don't change from one list to the other.

Any ideia?

Thanks in adavance for any help given.

Hello...

So let me understand this...

1. the second character always becomes an 'r'.
2. then there are 2 digits, and some number of characters (your example shows one 2 and two 3 character groups) that you don't change in the second list.
3. followed by 2 digits that do change in the second list, and always to a '01' and '02'.

Have I got that right? If I have then you might be able to do this with a pattern/substitution (or maybe 2 of them) inside a foreach loop...

foreach $word (@list) {
chomp($word); # just in case has newline
$word =~ s/s/r/;
$word =~ s/(\d\d\w+)/$1 . 01\n$1 . 02\n/;
$bigword = $bigword . $word;
}
(@new_list) = $bigword; # you concatenated everything into $bigword with newlines, so they should parse into the array by themselves ...

I have no idea of this would work, but it might... Otherwise there are other approaches, mainly to extract the second pattern above and just build the list element by element yourself....

$newctr = 0;
foreach $word (@list){
$word =~ /^(\w)/;
$first_letter = $1;
$word =~ /(\d\d\w+)/
$group = $1;
$new_list[$newctr] = $first_letter . 'r' . $group . "01";
$new_list[$newctr + 1] = $first_letter . 'r' . $group . "02";
$newctr += 2;
}

Now that I know will work, but it isn't very elegant.....